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Photons launched from a mobile platform

Phoenix_of_the_ashes

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If c = 2.998 10^8 if the speed of light, then what would happen if I launched photons from a surface which is moving a some speed > 0?

And relative to which plane is c measured from?
 

insomniac

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From the point of view of the platform moving at v>0? The photons travel at 2.998 x 10^8 m/s.

From a "stationary" observer or any other point of view...2.998 x 10^8.

The speed of light is the same from all frames of reference...hence the term "relativity". No matter how fast the object emitting photons is traveling, every observer moving at every speed will see the photons traveling at speed of c.

Solve the equations relating distance and time, and you'll find that distances appear shorter (length contraction) and time appears to slow on moving objects.
 

Marcopolo

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This is one of the problems that Einstein was so famous for solving. To put it in simple terms, the speed of light never changes, the rest of the Universe changes to accomondate the constant speed of light. That is why time slows down, and ultimately stops if the speed of light is theroetically reached, for a person who is moving faster through the universe.
 
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Vincent

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Originally posted by Nocturnal
Like he said, this is not a place for you to have people do your homework for you.
This isn't a HW problem. This is just a hypothetical discussion. This is like Graduate level physics, no one here could come close to knowing anything about it, it's just speculation.
 

Jvesti

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why that's simple.

you simply align the corbiside with the minefrabin enabler. To do this you must make a few tweaks in the orange continuum flow duct.

Once you do this you should be on your way to cube power the photon enabler diodes. Sit back and watch magic happen my friend.
 

diplomatic_lies

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The entire universe moves for the speed of light? The universe must be one hell of an AFC!!!!
 

InsidiousNstinct

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*is taking a remedial algebra class * :(
 

Create Reality

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So you are saying it's like a bullet catching up to a speeding train, the bullet being light and the train being the observer? As the train moves towards the speed of light the rate at which the bullet will intercept the train decreases. If both speeds = the speed of light then the bullet is 'frozen', or rather in sync with the train, and it only appears that time is frozen?
 
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